PH 구하는 법(Weak Acid, Buffer solution, After reaction) 간단하게 구하는 방법에 대해서 설명합니다.




pH 계산 문제 소개

안녕하세요, 오늘은 화학에서 자주 다루는 pH 계산 문제를 소개해드리려고 합니다. pH 계산은 산성도와 염기성을 이해하는 데 필수적인 개념으로, 다양한 상황에서 사용됩니다. 이번 포스트에서는 몇 가지 pH 계산 문제를 통해 개념을 쉽게 이해하고 연습할 수 있도록 도와드리겠습니다.









pH Calculation Problems

Problem 1: Calculate the pH of a 0.01 M HCl solution.

HCl is a strong acid that fully dissociates in water. Thus, [H+] = 0.01 M. The pH is calculated as follows: pH = -log(0.01) = 2.

Problem 2: Calculate the pH of a 0.1 M acetic acid solution (Ka = 1.8 × 10-5).

For a weak acid, [H+] = √(Ka · [HA]). Thus, [H+] = √(1.8 × 10-5 × 0.1) = 1.34 × 10-3 M. The pH is: pH = -log(1.34 × 10-3) ≈ 2.87.

Problem 3: Calculate the pH of a buffer solution containing 0.1 M acetic acid and 0.05 M sodium hydroxide (pKa = 4.74).

The reaction between acetic acid and sodium hydroxide produces acetate ion and water. The buffer solution contains 0.1 M acetate ion and 0.1 M acetic acid. Using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]) = 4.74 + log(0.1/0.1) = 4.74.

Problem 4: Calculate the pH of a 0.025 M HNO3 solution.

HNO3 is a strong acid that fully dissociates in water. Thus, [H+] = 0.025 M. The pH is calculated as follows: pH = -log(0.025) ≈ 1.60.

Problem 5: Calculate the pH of a 0.05 M ammonia solution (Kb = 1.8 × 10-5).

For a weak base, [OH-] = √(Kb · [B]). Thus, [OH-] = √(1.8 × 10-5 × 0.05) = 9.49 × 10-4 M. The pOH is: pOH = -log(9.49 × 10-4) = 3.02. The pH is: pH = 14 - pOH = 14 - 3.02 = 10.98.

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