Ap chem 프린스턴 화학 summary part 2

JjangJi's All About AP Chemistry Concept Lecture

Lesson 2: Chemical Bonding (1)


Types of Bonding vs. Types of Substances

Metallic Bond: Formed by the delocalization of electrons in a metal lattice. Electrons are free to move, creating a "sea of electrons" that accounts for properties like conductivity and malleability.

Ionic Bond: Formed by electrostatic attraction between oppositely charged ions. Typically occurs between metals and nonmetals, resulting in the formation of ionic compounds with high melting points.

Covalent Bond: Formed by the sharing of electrons between atoms. Covalent bonding leads to the formation of molecules and can result in different types of substances like molecular compounds and network solids.

Where:

Bond Breaking and Bond Forming

  • Bond Breaking: Endothermic process (requires energy input).
  • Bond Forming: Exothermic process (releases energy).

Understanding the energy changes involved in chemical reactions is crucial for predicting reaction spontaneity and calculating enthalpy changes.

Types of Crystals

  • Metallic Crystals: Consist of metal cations surrounded by a sea of delocalized valence electrons. These are good conductors of electricity and heat.
  • Ionic Crystals: Composed of alternating cations and anions held together by strong electrostatic forces. They are hard, brittle, and have high melting points.
  • Covalent Crystals (Network Solids): Atoms connected by covalent bonds in a continuous network. Examples include diamond (C), silicon (Si), and silicon dioxide (SiO2), which are hard and have very high melting points.
  • Molecular Crystals: Consist of molecules held together by intermolecular forces like London dispersion forces, dipole-dipole interactions, or hydrogen bonds. They generally have low melting points.

Properties of Different Types of Solids

Type of Solid Properties Examples
Metallic Solids
  • Good conductors of heat and electricity
  • Malleable and ductile
  • Variable melting points
Iron (Fe), Copper (Cu), Gold (Au)
Ionic Solids
  • High melting and boiling points
  • Brittle and hard
  • Conduct electricity when molten or dissolved
Sodium Chloride (NaCl), Magnesium Oxide (MgO)
Network Covalent Solids
  • Very high melting points
  • Hard and rigid
  • Do not conduct electricity (except graphite)
Diamond (C), Silicon (Si), Silicon Dioxide (SiO2)
Molecular Solids
  • Low melting and boiling points
  • Soft and brittle
  • Do not conduct electricity
Ice (H2O), Dry Ice (CO2)

Metallic Bond

Free Electrons: Delocalized electrons (valence electrons) that are free to move throughout the metal lattice.

Bond Strength: Can be compared using Coulomb’s Law:

$$ F = k \dfrac{q_1 q_2}{r} $$

Examples:

  • Li < Mg (Lithium has a weaker metallic bond than magnesium due to fewer delocalized electrons and a larger atomic radius.)
  • Li > Na (Lithium has a stronger metallic bond than sodium because lithium atoms are smaller, resulting in stronger attractions between nuclei and delocalized electrons.)

Alloys:

  • Interstitial Alloy: Formed when small atoms fill the interstitial spaces (holes) in a metal lattice (e.g., steel, where carbon atoms fit into iron lattice).
  • Substitutional Alloy: Formed when atoms of similar radii substitute for metal atoms in the lattice (e.g., brass, where zinc atoms replace some copper atoms).

Ionic Bond

Bond Strength: Compared using Coulomb’s Law:

$$ F = k \dfrac{q_1 q_2}{r} $$

Examples:

  • LiF > NaCl (Lithium fluoride has stronger ionic bonds than sodium chloride due to smaller ionic radii and higher charge density.)
  • LiF < MgO (Magnesium oxide has stronger ionic bonds because of higher charges on the ions, Mg2+ and O2-, compared to Li+ and F-.)

Lattice Energy:

The energy required to separate one mole of an ionic solid into its gaseous ions:

$$ XY(s) \rightarrow X^+(g) + Y^-(g) $$

Lattice energy is proportional to bond strength and can be predicted using Coulomb's Law.

Example: The lattice structure of NaCl consists of alternating Na+ and Cl- ions in a cubic arrangement.


Covalent Bond

Understanding covalent bond formation in terms of potential energy.

Bond Polarity vs. Molecular Polarity:

  • Polar Covalent Bond: Unequal sharing of electrons between atoms with different electronegativities, resulting in a dipole moment.
  • Nonpolar Covalent Bond: Equal sharing of electrons between atoms with similar electronegativities.

Key Terms:

  • Polar Molecules: Molecules with an asymmetric arrangement of polar bonds, resulting in a net dipole moment.
  • Nonpolar Molecules: Molecules with symmetrical arrangements or only nonpolar bonds, resulting in no net dipole moment.

Potential Energy vs. Distance in Bond Formation

Graph of H2 Bond Formation:

Bond Energy:

  • The energy required to dissociate the bond.
  • The net energy for stabilizing the bond.

Bond Length:

  • The distance between two nuclei at the minimum potential energy.
  • The distance where attractive and repulsive forces are balanced.

Potential Energy Graph:

At the lowest point in the graph, the bond is at its most stable energy state (approximately 0.74 Å for the H2 bond).

Concepts:

  • Bond energy is directly related to bond strength.
  • As atoms approach each other, repulsive forces increase until they reach an optimal distance where potential energy is minimized.

Molecular Geometry

VSEPR Theory:

Valence Shell Electron Pair Repulsion theory states that electron pairs arrange themselves to minimize repulsion, determining the molecular geometry.

Hybridization: Involves the mixing of atomic orbitals to form new hybrid orbitals:

  • sp hybridization: Linear geometry.
  • sp2 hybridization: Trigonal planar geometry.
  • sp3 hybridization: Tetrahedral geometry.

Order of Increasing Repulsion:

  • Bonding pair – bonding pair < lone pair – bonding pair < lone pair – lone pair.

Examples of Molecular Geometry:

  • Linear: 180° bond angle (e.g., CO2).
  • Trigonal Planar: 120° bond angle (e.g., BF3).
  • Tetrahedral: 109.5° bond angle (e.g., CH4).
  • Trigonal Pyramidal: Less than 109.5° bond angle due to lone pair (e.g., NH3).
  • Bent: Less than 120° or 109.5° bond angle depending on hybridization (e.g., H2O).

More Complex Geometries:

  • Trigonal Bipyramidal: 90°, 120° bond angles (e.g., PCl5).
  • Octahedral: 90° bond angles (e.g., SF6).
  • Square Planar: 90° bond angles, typically with d8 metal complexes (e.g., XeF4).

Question 1: Boron Trifluoride (BF3)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

BF3 has a trigonal planar geometry with sp2 hybridization. Boron has three bonding pairs and no lone pairs.

Correct Answer: Trigonal Planar, sp2 hybridization


Question 2: Phosphorus Trichloride (PCl3)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

PCl3 has a trigonal pyramidal geometry with sp3 hybridization. Phosphorus has three bonding pairs and one lone pair.

Correct Answer: Trigonal Pyramidal, sp3 hybridization


Question 3: Triiodide Ion (I3-)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

I3- has a linear geometry with sp3d hybridization. The central iodine atom has two bonding pairs and three lone pairs.

Correct Answer: Linear, sp3d hybridization


Question 4: Nitrite Ion (NO2-)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

NO2- has a bent geometry with sp2 hybridization. Nitrogen has two bonding pairs and one lone pair.

Correct Answer: Bent, sp2 hybridization


Question 5: Nitrate Ion (NO3-)

Task: Determine the molecular geometry and hybridization.

해답 보기

Answer Explanation:

NO3- has a trigonal planar geometry with sp2 hybridization. Nitrogen has three bonding pairs and no lone pairs.

Correct Answer: Trigonal Planar, sp2 hybridization


Question 6:

Which of the following compounds has the highest lattice energy?

Options:

  • (A) Sodium Chloride (NaCl)
  • (B) Lithium Fluoride (LiF)
  • (C) Magnesium Oxide (MgO)
  • (D) Potassium Bromide (KBr)
해답 보기

Answer Explanation:

Lattice energy increases with higher charges on the ions and smaller ionic radii. Magnesium Oxide (MgO) has Mg2+ and O2- ions, resulting in a higher lattice energy compared to the other compounds with lower charges.

Correct Answer: (C) Magnesium Oxide (MgO)


Question 7:

Which of the following substances is most likely to form an ionic bond based on its properties?

Options:

  • (A) Gold (Au)
  • (B) Sodium Chloride (NaCl)
  • (C) Methane (CH4)
  • (D) Carbon Dioxide (CO2)
View Answer

Answer Explanation:

Ionic bonds are formed through the electrostatic attraction between oppositely charged ions, typically between metals and nonmetals. Characteristics of ionic compounds include high melting points, brittleness, and the ability to conduct electricity when molten or dissolved in water.

  • Option A: Gold (Au) is a metal that typically forms metallic bonds, not ionic bonds.
  • Option B: Sodium Chloride (NaCl) is composed of sodium (a metal) and chlorine (a nonmetal), and it forms an ionic bond. It exhibits high melting points and conducts electricity when dissolved or molten, which are characteristic properties of ionic compounds.
  • Option C: Methane (CH4) is a molecular compound that forms covalent bonds through the sharing of electrons between carbon and hydrogen atoms.
  • Option D: Carbon Dioxide (CO2) is also a molecular compound that forms covalent bonds between carbon and oxygen atoms.

Therefore, the substance most likely to form an ionic bond is:

Correct Answer: (B) Sodium Chloride (NaCl)


Question 8:

Which of the following statements best explains why metallic solids are good conductors of electricity?

Options:

  • (A) They have high lattice energies.
  • (B) Their electrons are localized and tightly bound to individual atoms.
  • (C) They consist of a lattice of cations surrounded by a sea of delocalized electrons.
  • (D) They form discrete molecules with strong intermolecular forces.
해답 보기

Answer Explanation:

Metallic solids conduct electricity because the delocalized electrons can move freely throughout the metal lattice, allowing the flow of electric current.

Correct Answer: (C) They consist of a lattice of cations surrounded by a sea of delocalized electrons.


Question 9:

During a chemical reaction, bond breaking requires energy input while bond forming releases energy. Which of the following scenarios correctly identifies these processes?

Options:

  • (A) Breaking a covalent bond in methane is exothermic, and forming an ionic bond in sodium chloride is endothermic.
  • (B) Breaking an ionic bond in sodium chloride is endothermic, and forming a metallic bond in copper is exothermic.
  • (C) Breaking a metallic bond in iron is exothermic, and forming a covalent bond in water is endothermic.
  • (D) Breaking a hydrogen bond in water is exothermic, and forming a covalent bond in carbon dioxide is exothermic.
View Answer

Answer Explanation:

Bond breaking is an endothermic process as it requires energy input to overcome the bond energy. Bond forming is an exothermic process as it releases energy when bonds are formed.

  • Option A: Incorrect. Breaking a covalent bond is endothermic, not exothermic. Forming an ionic bond is typically exothermic.
  • Option B: Correct. Breaking an ionic bond in sodium chloride requires energy input (endothermic), and forming a metallic bond in copper releases energy (exothermic).
  • Option C: Incorrect. Breaking a metallic bond is endothermic, not exothermic. Forming a covalent bond is exothermic, not endothermic.
  • Option D: Incorrect. Breaking a hydrogen bond is endothermic, not exothermic. Forming a covalent bond is exothermic, which contradicts the first part.

Therefore, the correct scenario is:

Correct Answer: (B) Breaking an ionic bond in sodium chloride is endothermic, and forming a metallic bond in copper is exothermic.


Question 10:

Compare the bond strength of Lithium Fluoride (LiF) and Sodium Chloride (NaCl). Which compound has a stronger ionic bond and why?

Options:

  • (A) LiF has a stronger ionic bond because Li+ and F- have higher charges than Na+ and Cl-.
  • (B) NaCl has a stronger ionic bond because Na+ and Cl- are larger ions, increasing electrostatic attraction.
  • (C) LiF has a stronger ionic bond because it has smaller ionic radii, leading to greater charge density.
  • (D) Both have similar bond strengths due to similar ionic charges.
해답 보기

Answer Explanation:

LiF has smaller ions compared to NaCl, resulting in higher charge density and stronger electrostatic attractions between the ions, leading to a stronger ionic bond.

Correct Answer: (C) LiF has a stronger ionic bond because it has smaller ionic radii, leading to greater charge density.


Question 11:

Which of the following molecular geometries corresponds to a molecule with two bonding pairs and two lone pairs on the central atom?

Options:

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Tetrahedral
  • (D) Bent
해답 보기

Answer Explanation:

A molecule with two bonding pairs and two lone pairs has a bent molecular geometry due to the repulsion from the lone pairs.

Correct Answer: (D) Bent


Question 12:

Which of the following molecules has sp3 hybridization at the central atom?

Options:

  • (A) CO2
  • (B) BF3
  • (C) CH4
  • (D) SO3
해답 보기

Answer Explanation:

CH4 (methane) has four bonding pairs around the central carbon atom, resulting in sp3 hybridization.

Correct Answer: (C) CH4


Question 13:

Which of the following molecules has a see-saw molecular geometry?

Options:

  • (A) SF4
  • (B) PF5
  • (C) XeF4
  • (D) BF3
View Answer
   

Answer Explanation:

SF4 has a see-saw molecular geometry due to the presence of one lone pair and four bonding pairs around the central sulfur atom.

Correct Answer: (A) SF4


Question 14:

Which of the following best explains why covalent crystals like diamond have very high melting points?

Options:

  • (A) They consist of discrete molecules held together by weak intermolecular forces.
  • (B) They have a continuous network of strong covalent bonds throughout the structure.
  • (C) They contain delocalized electrons that facilitate strong metallic bonding.
  • (D) They are composed of ions held together by strong electrostatic forces.
해답 보기

Answer Explanation:

Covalent crystals like diamond have a continuous network of strong covalent bonds, requiring significant energy to break these bonds, resulting in very high melting points.

Correct Answer: (B) They have a continuous network of strong covalent bonds throughout the structure.


Question 15:

Which of the following properties is most characteristic of metallic bonding in a substance?

Options:

  • (A) High electrical conductivity in both solid and liquid states.
  • (B) High melting point but poor electrical conductivity in solid form.
  • (C) Low melting point and formation of discrete molecules.
  • (D) Solubility in polar solvents like water.
View Answer

Answer Explanation:

Metallic bonding is characterized by the "sea of electrons" that are free to move throughout the lattice of metal cations. This delocalization of electrons allows metals to conduct electricity in both solid and liquid forms.

  • Option A: Correct. The free movement of electrons within the metallic lattice enables electrical conductivity in both states.
  • Option B: This describes ionic solids, which conduct electricity only when molten or dissolved in water.
  • Option C: This is characteristic of molecular (covalent) compounds, not metallic solids.
  • Option D: Metallic substances are not typically soluble in polar solvents like water.

Correct Answer: (A) High electrical conductivity in both solid and liquid states.


Question 16:

Which of the following molecules exhibits hydrogen bonding?

Options:

  • (A) CH4
  • (B) H2S
  • (C) NH3
  • (D) CO2
해답 보기

Answer Explanation:

NH3 (ammonia) exhibits hydrogen bonding due to the presence of hydrogen atoms bonded to nitrogen, a highly electronegative atom.

Correct Answer: (C) NH3


Question 17:

Explain why Lithium (Li) has a stronger metallic bond compared to Sodium (Na).

Options:

  • (A) Lithium has more delocalized electrons than Sodium.
  • (B) Lithium atoms are larger, resulting in stronger attractions.
  • (C) Lithium has a higher effective nuclear charge, leading to stronger attractions between the nuclei and delocalized electrons.
  • (D) Lithium forms interstitial alloys more readily than Sodium.
해답 보기

Answer Explanation:

Lithium has a smaller atomic radius and a higher effective nuclear charge compared to sodium, resulting in stronger attractions between the metal cations and the delocalized electrons, leading to stronger metallic bonds.

Correct Answer: (C) Lithium has a higher effective nuclear charge, leading to stronger attractions between the nuclei and delocalized electrons.


Question 18:

Which of the following substances is expected to conduct electricity in its solid state?

Options:

  • (A) Diamond (C)
  • (B) Sodium Chloride (NaCl)
  • (C) Graphite (C)
  • (D) Ice (H2O)
해답 보기

Answer Explanation:

Graphite conducts electricity in its solid state due to the presence of delocalized electrons within its layered structure. The other substances do not conduct electricity when solid.

Correct Answer: (C) Graphite (C)


Question 19:

Which type of molecular geometry is associated with a molecule that has three bonding pairs and one lone pair around the central atom?

Options:

  • (A) Tetrahedral
  • (B) Trigonal Pyramidal
  • (C) Bent
  • (D) Trigonal Planar
해답 보기

Answer Explanation:

A molecule with three bonding pairs and one lone pair has a trigonal pyramidal geometry due to the repulsion caused by the lone pair.

Correct Answer: (B) Trigonal Pyramidal


Question 20:

Which of the following substances is an example of a network covalent solid, characterized by very high melting points and hardness?

Options:

  • (A) Sodium Chloride (NaCl)
  • (B) Graphite (C)
  • (C) Methane (CH4)
  • (D) Magnesium (Mg)
View Answer

Answer Explanation:

Network covalent solids are characterized by a continuous network of covalent bonds throughout the material, resulting in extremely high melting points and hardness. Graphite and diamond are classic examples of network covalent solids formed by carbon atoms.

  • Option A: Sodium chloride is an ionic solid, not a network covalent solid.
  • Option B: Correct. Graphite is a network covalent solid composed of carbon atoms in a hexagonal lattice.
  • Option C: Methane is a molecular compound with covalent bonds, but it is not a network covalent solid.
  • Option D: Magnesium is a metallic solid, not a network covalent solid.

Correct Answer: (B) Graphite (C)


Question 21:

Which of the following molecular geometries has bond angles of approximately 109.5°?

Options:

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Tetrahedral
  • (D) Bent
해답 보기

Answer Explanation:

Tetrahedral geometry has bond angles of approximately 109.5°, as seen in molecules like methane (CH4).

Correct Answer: (C) Tetrahedral


Question 39:

Which of the following molecules is nonpolar even though it contains polar bonds?

Options:

  • (A) H2O (Water)
  • (B) CO2 (Carbon Dioxide)
  • (C) NH3 (Ammonia)
  • (D) HF (Hydrogen Fluoride)
View Answer

Answer Explanation:

Carbon dioxide (CO2) has polar bonds, but its linear shape causes the dipole moments to cancel out, resulting in a nonpolar molecule.

Correct Answer: (B) CO2


Question 23:

Which of the following statements correctly describes the relationship between bond length and bond strength?

Options:

  • (A) Shorter bond lengths correspond to weaker bonds.
  • (B) Longer bond lengths correspond to stronger bonds.
  • (C) Shorter bond lengths correspond to stronger bonds.
  • (D) Bond length and bond strength are independent of each other.
해답 보기

Answer Explanation:

Shorter bond lengths generally correspond to stronger bonds because the atoms are held together more tightly by the overlapping electron orbitals.

Correct Answer: (C) Shorter bond lengths correspond to stronger bonds.


Question 24:

Which type of intermolecular force is primarily responsible for the high boiling point of water (H2O)?

Options:

  • (A) London dispersion forces
  • (B) Dipole-dipole interactions
  • (C) Hydrogen bonding
  • (D) Ionic bonding
해답 보기

Answer Explanation:

Hydrogen bonding is responsible for the high boiling point of water. The hydrogen atoms in water form strong hydrogen bonds with the oxygen atoms of neighboring water molecules.

Correct Answer: (C) Hydrogen bonding


Question 25:

Which of the following best explains why graphite can conduct electricity while diamond cannot?

Options:

  • (A) Graphite has a continuous network of covalent bonds, whereas diamond has discrete molecules.
  • (B) Graphite has delocalized electrons that can move freely, whereas diamond does not.
  • (C) Diamond has higher lattice energy than graphite.
  • (D) Graphite forms ionic bonds, while diamond forms covalent bonds.
해답 보기

Answer Explanation:

Graphite has delocalized electrons within its layers that can move freely, allowing it to conduct electricity. Diamond lacks these delocalized electrons, making it an electrical insulator.

Correct Answer: (B) Graphite has delocalized electrons that can move freely, whereas diamond does not.


Question 26:

Which of the following statements correctly explains the difference in hardness between diamond and graphite?

Options:

  • (A) Diamond has a layered structure, whereas graphite has a tetrahedral network.
  • (B) Diamond has strong covalent bonds in all directions, whereas graphite has strong bonds within layers but weak forces between layers.
  • (C) Graphite has stronger intermolecular forces than diamond.
  • (D) Graphite has a higher lattice energy than diamond.
해답 보기

Answer Explanation:

Diamond is extremely hard because it has a three-dimensional network of strong covalent bonds in all directions. Graphite, on the other hand, has strong covalent bonds within its layers but weak van der Waals forces between layers, making it soft and slippery.

Correct Answer: (B) Diamond has strong covalent bonds in all directions, whereas graphite has strong bonds within layers but weak forces between layers.


Question 27:

Why do ionic solids generally have higher melting points compared to molecular solids?

Options:

  • (A) Ionic solids are held together by weaker intermolecular forces.
  • (B) Ionic solids have stronger electrostatic forces of attraction between ions.
  • (C) Molecular solids have a continuous network of covalent bonds.
  • (D) Molecular solids contain delocalized electrons.
해답 보기

Answer Explanation:

Ionic solids are held together by strong electrostatic attractions between oppositely charged ions, requiring more energy to break these bonds compared to the weaker intermolecular forces in molecular solids.

Correct Answer: (B) Ionic solids have stronger electrostatic forces of attraction between ions.


Question 28:

According to Coulomb’s Law, which of the following factors does NOT directly affect the strength of an ionic bond?

Options:

  • (A) The magnitude of the charges on the ions.
  • (B) The distance between the centers of the ions.
  • (C) The number of electrons in the outermost shell of the ions.
  • (D) The types of ions involved.
View Answer

Answer Explanation:

Coulomb’s Law describes the electrostatic force between two charged particles and is given by:

$$ F = k \dfrac{q_1 q_2}{r^2} $$

Where:

  • F is the force between the charges.
  • k is Coulomb’s constant.
  • q1 and q2 are the magnitudes of the charges.
  • r is the distance between the centers of the two ions.
  • Option A: The magnitude of the charges on the ions directly affects the strength of the ionic bond. Higher charges result in stronger bonds.
  • Option B: The distance between the centers of the ions inversely affects the bond strength. Greater distances weaken the bond.
  • Option C: The number of electrons in the outermost shell does NOT directly affect the strength of the ionic bond as described by Coulomb’s Law. While the number of electrons can influence the formation of ions, Coulomb’s Law specifically relates to the charges and distance between ions.
  • Option D: The types of ions involved can affect factors like charge magnitude and ionic radii, thereby indirectly influencing bond strength.

Therefore, the factor that does NOT directly affect the strength of an ionic bond according to Coulomb’s Law is:

Correct Answer: (C) The number of electrons in the outermost shell of the ions.


Question 29:

Which of the following compounds contains both ionic and covalent bonds?

Options:

  • (A) Sodium Chloride (NaCl)
  • (B) Carbon Dioxide (CO2)
  • (C) Ammonium Nitrate (NH4NO3)
  • (D) Methane (CH4)
View Answer

Answer Explanation:

A compound containing both ionic and covalent bonds will have ions held together by ionic bonds, while those ions themselves contain covalent bonds within.

  • Option A: Sodium chloride contains only ionic bonds between sodium and chloride ions.
  • Option B: Carbon dioxide contains only covalent bonds between carbon and oxygen atoms.
  • Option C: Correct. Ammonium nitrate contains ionic bonds between the ammonium (NH4+) and nitrate (NO3-) ions, and covalent bonds within the ammonium and nitrate ions themselves.
  • Option D: Methane contains only covalent bonds between carbon and hydrogen atoms.

Correct Answer: (C) Ammonium Nitrate (NH4NO3)


Question 30:

Which of the following best explains why water (H2O) has a higher boiling point compared to hydrogen sulfide (H2S)?

Options:

  • (A) H2O has stronger hydrogen bonding than H2S.
  • (B) H2S has a more polar covalent bond than H2O.
  • (C) H2O has weaker intermolecular forces than H2S.
  • (D) H2S is a network covalent solid while H2O is a molecular solid.
해답 보기

Answer Explanation:

Water exhibits strong hydrogen bonding due to the highly electronegative oxygen atom bonded to hydrogen, leading to higher boiling points. Hydrogen sulfide has weaker dipole-dipole interactions and cannot form hydrogen bonds as effectively.

Correct Answer: (A) H2O has stronger hydrogen bonding than H2S.


Question 31:

Which of the following best explains why magnesium (Mg) has a stronger metallic bond than lithium (Li)?

Options:

  • (A) Magnesium has more delocalized electrons than lithium.
  • (B) Magnesium has a larger atomic radius than lithium.
  • (C) Magnesium has a higher ionization energy than lithium.
  • (D) Magnesium has a lower electronegativity than lithium.
해답 보기

Answer Explanation:

Magnesium has more delocalized electrons (two valence electrons) compared to lithium (one valence electron), leading to stronger metallic bonding due to greater electrostatic attraction between the metal cations and the sea of delocalized electrons.

Correct Answer: (A) Magnesium has more delocalized electrons than lithium.


Question 32:

Based on Coulomb's Law, which of the following ionic compounds would have the greatest lattice energy, considering both ion charge and ionic radius?

Options:

  • (A) CaO
  • (B) AlN
  • (C) SrS
  • (D) KF
View Answer

Answer Explanation:

Lattice energy is directly proportional to the product of the charges on the ions and inversely proportional to the sum of the ionic radii. AlN has Al3+ and N3-, resulting in a much higher charge product than the other compounds. Additionally, both aluminum and nitrogen have relatively small ionic radii, which further increases the lattice energy.

Correct Answer: (B) AlN


Question 33:

Which of the following molecular geometries corresponds to a molecule with sp3 hybridization and one lone pair?

Options:

  • (A) Trigonal Planar
  • (B) Tetrahedral
  • (C) Trigonal Pyramidal
  • (D) Linear
해답 보기

Answer Explanation:

Sp3 hybridization with one lone pair results in a trigonal pyramidal geometry, as seen in molecules like NH3.

Correct Answer: (C) Trigonal Pyramidal


Question 34:

Which of the following best explains why silicon (Si) is classified as a network covalent solid rather than a molecular solid?

Options:

  • (A) Silicon forms discrete Si4 molecules held together by van der Waals forces.
  • (B) Silicon atoms are bonded in a continuous 3D network through strong covalent bonds.
  • (C) Silicon forms metallic bonds with delocalized electrons.
  • (D) Silicon exists as individual atoms in the solid state.
해답 보기

Answer Explanation:

Silicon forms a continuous three-dimensional network of covalent bonds, similar to diamond, which classifies it as a network covalent solid.

Correct Answer: (B) Silicon atoms are bonded in a continuous 3D network through strong covalent bonds.


Question 35:

Which of the following statements accurately explains the trend in bond energy and bond length for a series of covalent bonds involving the same atoms?

Options:

  • (A) Triple bonds have lower bond energies and longer bond lengths compared to single bonds.
  • (B) Double bonds are longer than single bonds but have lower bond energies.
  • (C) As the number of shared electron pairs between two atoms increases, the bond length decreases and bond energy increases.
  • (D) Single, double, and triple bonds all have the same bond energy regardless of their bond length.
View Answer

Answer Explanation:

As the number of shared electron pairs between two atoms increases (moving from single to double to triple bonds), the atoms are pulled closer together, resulting in shorter bond lengths and higher bond energies due to the increased attraction between the nuclei and shared electrons.

Correct Answer: (C) As the number of shared electron pairs between two atoms increases, the bond length decreases and bond energy increases.


Question 36:

Which of the following statements correctly distinguishes between interstitial and substitutional alloys?

Options:

  • (A) Interstitial alloys are formed by atoms of similar radii replacing each other in the lattice, while substitutional alloys have smaller atoms filling the interstitial spaces.
  • (B) Substitutional alloys are formed by atoms of different radii filling interstitial spaces, while interstitial alloys have similar-sized atoms replacing each other.
  • (C) Interstitial alloys are formed by atoms of different radii filling interstitial spaces in the lattice, while substitutional alloys are formed by atoms of comparable radii replacing metal atoms in the lattice.
  • (D) Both interstitial and substitutional alloys are formed exclusively by atoms of similar radii.
해답 보기

Answer Explanation:

Interstitial alloys involve smaller atoms fitting into the interstitial spaces (holes) of a metal lattice, while substitutional alloys involve atoms of similar size replacing some of the metal atoms in the lattice.

Correct Answer: (C) Interstitial alloys are formed by atoms of different radii filling interstitial spaces in the lattice, while substitutional alloys are formed by atoms of comparable radii replacing metal atoms in the lattice.


Question 37:

Considering lattice energy and bond strength, arrange the following ionic compounds in order from highest to lowest lattice energy:

Options:

  • (A) MgO > LiF > NaCl > KBr
  • (B) LiF > MgO > NaCl > KBr
  • (C) NaCl > MgO > LiF > KBr
  • (D) KBr > NaCl > LiF > MgO
해답 보기

Answer Explanation:

Lattice energy increases with higher charges and smaller ionic radii. MgO has the highest lattice energy due to the +2 and -2 charges and small sizes. LiF follows with +1 and -1 charges but smaller ions than NaCl and KBr.

Correct Answer: (A) MgO > LiF > NaCl > KBr


Question 38:

Which of the following molecules exhibits resonance structures due to delocalized electrons?

Options:

  • (A) Methane (CH4)
  • (B) Ethane (C2H6)
  • (C) Benzene (C6H6)
  • (D) Carbon tetrachloride (CCl4)
해답 보기

Answer Explanation:

Benzene (C₆H₆) has alternating double and single bonds between carbon atoms in a ring structure. These bonds can be represented by multiple resonance structures, where the position of the double bonds shifts around the ring. This delocalization of electrons provides additional stability to the molecule.

Correct Answer: (C) Benzene (C₆H₆)


Question 39:

How does bond polarity relate to molecular polarity?

Options:

  • (A) All molecules with polar bonds are polar.
  • (B) A molecule can be nonpolar even if it has polar bonds .
  • (C) Molecules with nonpolar bonds are always nonpolar.
  • (D) Molecular polarity is not related to bond polarity.
View Answer

Answer Explanation:

A molecule can have polar bonds but be nonpolar if the molecular geometry allows the dipole moments to cancel out.

Correct Answer: (B)


Question 40:

Which of the following molecules has a trigonal pyramidal geometry and is polar due to the presence of a lone pair on the central atom?

Options:

  • (A) Carbon Tetrachloride (CCl4)
  • (B) Ammonia (NH3)
  • (C) Boron Trifluoride (BF3)
  • (D) Water (H2O)
View Answer

Answer Explanation:

A trigonal pyramidal molecular geometry occurs when there are three bonding pairs and one lone pair on the central atom. The lone pair causes a distortion from a perfect tetrahedral shape, resulting in polarity.

  • Option A: Carbon tetrachloride has a tetrahedral geometry and is nonpolar due to its symmetric shape.
  • Option B: Correct. Ammonia (NH3) has three bonding pairs and one lone pair on nitrogen, giving it a trigonal pyramidal shape. The lone pair creates an asymmetric charge distribution, making it polar.
  • Option C: Boron trifluoride has a trigonal planar geometry with no lone pairs on the central boron atom, making it nonpolar.
  • Option D: Water has a bent geometry, not trigonal pyramidal. It is polar due to its lone pairs, but its geometry is not trigonal pyramidal.

Correct Answer: (B) Ammonia (NH3)


Question 41:

Which of the following ions exhibits resonance due to delocalized electrons?

Options:

  • (A) Ammonium ion (NH4+)
  • (B) Sulfate ion (SO42-)
  • (C) Hydroxide ion (OH-)
  • (D) Sodium ion (Na+)
View Answer

Answer Explanation:

The sulfate ion (SO₄²⁻) exhibits resonance because the double bonds between sulfur and oxygen can be delocalized among the four oxygen atoms. This means that the actual structure is a hybrid of multiple resonance structures, providing extra stability to the ion.

Correct Answer: (B) Sulfate ion (SO42-)


Question 42:

In the formation of an ionic bond between Mg and O, which of the following correctly represents the electron transfer?

Options:

  • (A) Mg gains two electrons and O loses two electrons.
  • (B) Mg loses two electrons and O gains two electrons.
  • (C) Mg gains one electron and O loses one electron.
  • (D) Mg shares two electrons with O.
View Answer

Answer Explanation:

Magnesium (Mg) has two valence electrons and loses both to achieve a stable noble gas configuration, while oxygen (O) gains two electrons to complete its valence shell.

Correct Answer: (B) Mg loses two electrons and O gains two electrons.


Question 43:

Which of the following best explains why hydrogen fluoride (HF) has a higher boiling point compared to other hydrogen halides such as HCl, HBr, and HI?

Options:

  • (A) HF has stronger London dispersion forces than the other hydrogen halides.
  • (B) The hydrogen atom in HF is less shielded, allowing it to form stronger ionic bonds.
  • (C) HF forms strong hydrogen bonds due to the high electronegativity of fluorine, which is not present in the other hydrogen halides.
  • (D) HF molecules are smaller, allowing for closer packing and stronger dipole-dipole interactions.
View Answer

Answer Explanation:

The higher boiling point of HF is primarily due to strong hydrogen bonding. Fluorine's high electronegativity creates a significant dipole in the HF molecule, enabling the formation of hydrogen bonds. This intermolecular force is much stronger than the dipole-dipole interactions or London dispersion forces present in other hydrogen halides such as HCl, HBr, and HI.

Correct Answer: (C) HF forms strong hydrogen bonds due to the high electronegativity of fluorine, which is not present in the other hydrogen halides.


Question 44:

Which of the following molecular geometries has the highest number of electron pairs around the central atom?

Options:

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Tetrahedral
  • (D) Octahedral
View Answer

Answer Explanation:

Octahedral geometry has six electron pairs around the central atom, which is more than the other listed geometries.

Correct Answer: (D) Octahedral



Question 45:

Why does carbon (C) in its diamond form have a higher melting point than oxygen (O) in its molecular form?

Options:

  • (A) Diamond has stronger hydrogen bonds than oxygen molecules.
  • (B) Diamond has a network of covalent bonds, whereas oxygen forms only weak intermolecular forces.
  • (C) Oxygen molecules have a higher molecular weight than diamond.
  • (D) Diamond has delocalized electrons, while oxygen does not.
View Answer

Answer Explanation:

Diamond is a network covalent solid with each carbon atom bonded to four others in a 3D lattice, resulting in very strong bonds and a high melting point. Oxygen, being a molecular solid, only has weak intermolecular forces, leading to a much lower melting point.

Correct Answer: (B) Diamond has a network of covalent bonds, whereas oxygen forms only weak intermolecular forces.


Question 46:

Which of the following best explains why molecular solids generally have lower melting points compared to ionic solids?

Options:

  • (A) Molecular solids have stronger covalent bonds within their molecules.
  • (B) Molecular solids have weaker intermolecular forces compared to the strong electrostatic forces in ionic solids.
  • (C) Ionic solids are composed of larger ions than molecular solids.
  • (D) Ionic solids do not conduct electricity, unlike molecular solids.
View Answer

Answer Explanation:

Molecular solids are held together by relatively weak intermolecular forces (such as London dispersion forces, dipole-dipole interactions, or hydrogen bonds) compared to the strong electrostatic forces between ions in ionic solids, resulting in lower melting points.

Correct Answer: (B) Molecular solids have weaker intermolecular forces compared to the strong electrostatic forces in ionic solids.


Question 47:

Which of the following statements correctly explains the electrical conductivity of network covalent solids?

Options:

  • (A) Diamond can conduct electricity because all its electrons are free to move within the crystal lattice.
  • (B) Silicon can conduct electricity at room temperature due to the presence of free electrons in its structure.
  • (C) Graphite conducts electricity because it has delocalized electrons within its layers, while silicon and silicon dioxide do not have such free-moving electrons.
  • (D) Silicon dioxide (SiO2) can conduct electricity because its atoms are arranged in a regular, repeating pattern.
View Answer

Answer Explanation:

Graphite is unique among network covalent solids in its ability to conduct electricity. This is because it has delocalized electrons within its layered structure that can move freely, unlike diamond, silicon, or silicon dioxide, which do not have such free-moving electrons.

Correct Answer: (C) Graphite conducts electricity because it has delocalized electrons within its layers, while silicon and silicon dioxide do not have such free-moving electrons.


Question 48:

According to the VSEPR theory, what is the molecular geometry of sulfur dioxide (SO2)?

Options:

  • (A) Linear
  • (B) Trigonal Planar
  • (C) Trigonal Pyramidal
  • (D) Bent
View Answer

Answer Explanation:

SO2 has two bonding pairs and one lone pair around the central sulfur atom, resulting in a bent molecular geometry.

Correct Answer: (D) Bent


Question 49:

Which hybridization is associated with a trigonal bipyramidal molecular geometry?

Options:

  • (A) sp
  • (B) sp2
  • (C) sp3
  • (D) sp3d
View Answer

Answer Explanation:

Trigonal bipyramidal geometry involves sp3d hybridization, where one d orbital is involved in the hybridization process.

Correct Answer: (D) sp3d


Question 50:

Which of the following molecules has the lowest boiling point and why?

Options:

  • (A) Water (H2O)
  • (B) Methanol (CH3OH)
  • (C) Hydrogen Sulfide (H2S)
  • (D) Ammonia (NH3)
View Answer

Answer Explanation:

Hydrogen sulfide (H2S>) has the lowest boiling point among the options because it exhibits weaker hydrogen bonding compared to water, methanol, and ammonia, due to sulfur being less electronegative than oxygen and nitrogen.

Correct Answer: (C) Hydrogen Sulfide (H2S)


Question 51:

Which of the following best describes the role of delocalized electrons in metallic bonding?

Options:

  • (A) They form strong covalent bonds between metal atoms.
  • (B) They are localized between specific metal cations.
  • (C) They move freely throughout the metal lattice, allowing electrical conductivity.
  • (D) They are responsible for the formation of ionic bonds within the metal.
View Answer

Answer Explanation:

Delocalized electrons in metallic bonding are free to move throughout the metal lattice, which facilitates electrical conductivity and contributes to the malleable and ductile properties of metals.

Correct Answer: (C) They move freely throughout the metal lattice, allowing electrical conductivity.


Question 52:

Which of the following molecules is expected to have the greatest bond polarity?

Options:

  • (A) Cl2
  • (B) H2O
  • (C) CO2
  • (D) HF
View Answer

Answer Explanation:

Bond polarity arises from the difference in electronegativity between the bonded atoms. The greater the difference in electronegativity, the more polar the bond:

  • Option A: Cl2 has a bond between two identical chlorine atoms with no difference in electronegativity, making it nonpolar.
  • Option B: H2O has polar O-H bonds due to the electronegativity difference between oxygen and hydrogen, but the bond polarity is less than that of HF.
  • Option C: CO2 has polar C=O bonds, but the molecule is linear and symmetrical, resulting in a nonpolar overall molecule.
  • Option D: Correct. HF has the greatest electronegativity difference between hydrogen and fluorine, resulting in a highly polar bond.

Correct Answer: (D) HF


Question 53:

Which of the following statements is true about network covalent solids compared to molecular solids?

Options:

  • (A) Network covalent solids have lower melting points than molecular solids.
  • (B) Network covalent solids are typically soft and brittle.
  • (C) Network covalent solids do not conduct electricity.
  • (D) Network covalent solids have strong, extensive bonding throughout the structure.
View Answer

Answer Explanation:

Network covalent solids have strong, extensive covalent bonds throughout the entire structure, resulting in high melting points and hardness. Unlike molecular solids, they are rigid and hard due to the continuous network of bonds.

Correct Answer: (D) Network covalent solids have strong, extensive bonding throughout the structure.


Question 54:

Which of the following compounds is expected to be a good electrical conductor in the solid state?

Options:

  • (A) Diamond (C)
  • (B) Silicon Dioxide (SiO2)
  • (C) Graphite (C)
  • (D) Sodium Chloride (NaCl)
View Answer

Answer Explanation:

Graphite conducts electricity in the solid state due to the presence of delocalized electrons within its layers, allowing electrons to move freely. Diamond and silicon dioxide are non-conductors, and sodium chloride does not conduct electricity when solid.

Correct Answer: (C) Graphite (C)


Question 55:

Which of the following molecules is nonpolar despite having polar bonds?

Options:

  • (A) HCl
  • (B) CO2
  • (C) NH3
  • (D) HF
View Answer
   

Answer Explanation:

CO2 has polar C=O bonds, but the molecule is linear and symmetrical, causing the dipole moments to cancel out. Therefore, CO2 is a nonpolar molecule despite having polar bonds.

Correct Answer: (B) CO2


Question 56:

Which of the following best describes the hybridization of the central atom in methane (CH4)?

Options:

  • (A) sp
  • (B) sp2
  • (C) sp3
  • (D) dsp3
View Answer

Answer Explanation:

Methane (CH4) has a tetrahedral geometry, which corresponds to sp3 hybridization of the carbon atom.

Correct Answer: (C) sp3


Question 57:

Which of the following compounds would exhibit London dispersion forces as the primary intermolecular force?

Options:

  • (A) H2O
  • (B) CH4
  • (C) NH3
  • (D) HF
View Answer

Answer Explanation:

Methane (CH4) is a nonpolar molecule and relies primarily on London dispersion forces for intermolecular attractions.

Correct Answer: (B) CH4


Question 58:

Which of the following molecules exhibits a trigonal planar geometry?

Options:

  • (A) Methane (CH4)
  • (B) Ammonia (NH3)
  • (C) Boron Trifluoride (BF3)
  • (D) Water (H2O)
View Answer

Answer Explanation:

Trigonal planar geometry occurs when a central atom has three bonding pairs and no lone pairs of electrons, resulting in a bond angle of approximately 120°:

  • Option A: Methane (CH4) has a tetrahedral geometry with four bonding pairs and no lone pairs.
  • Option B: Ammonia (NH3) has a trigonal pyramidal geometry due to the presence of a lone pair on nitrogen.
  • Option C: Correct. Boron Trifluoride (BF3) has three bonding pairs and no lone pairs around the central boron atom, resulting in a trigonal planar geometry.
  • Option D: Water (H2O) has a bent geometry due to the two lone pairs on the oxygen atom.

Correct Answer: (C) Boron Trifluoride (BF3)


Question 59:

Which of the following best explains why network covalent solids generally have higher melting points than molecular solids?

Options:

  • (A) Network covalent solids have stronger intermolecular forces.
  • (B) Network covalent solids have extensive covalent bonding throughout the structure.
  • (C) Molecular solids have larger molecules, leading to weaker bonds.
  • (D) Molecular solids have delocalized electrons, making them more stable.
View Answer

Answer Explanation:

Network covalent solids are held together by strong, extensive covalent bonds throughout the entire structure, requiring significantly more energy to break compared to the weaker intermolecular forces in molecular solids.

Correct Answer: (B) Network covalent solids have extensive covalent bonding throughout the structure.


Question 60:

Which of the following molecules has a square planar geometry?

Options:

  • (A) XeF4
  • (B) SF4
  • (C) PF5
  • (D) ClF3
View Answer
   

Answer Explanation:

XeF4 has a square planar geometry due to the presence of two lone pairs and four bonding pairs around the central xenon atom.

Correct Answer: (A) XeF4


Question 61:

Which of the following molecules would exhibit the strongest dipole-dipole interactions in the liquid state?

Options:

  • (A) Carbon tetrachloride (CCl4)
  • (B) Ammonia (NH3)
  • (C) Sulfur hexafluoride (SF6)
  • (D) Methane (CH4)
View Answer

Answer Explanation:

Ammonia (NH3) has a trigonal pyramidal geometry with a lone pair on the nitrogen, creating a significant dipole moment. Additionally, the highly electronegative nitrogen atom forms hydrogen bonds with other ammonia molecules, resulting in strong dipole-dipole interactions in the liquid state. The other molecules either lack a significant dipole moment or do not form strong hydrogen bonds.

Correct Answer: (B) Ammonia (NH3)


Question 62:

Which of the following best explains why ammonia (NH3) has a higher boiling point than methane (CH4)?

Options:

  • (A) NH3 has a larger molecular weight than CH4.
  • (B) NH3 has stronger hydrogen bonds compared to the London dispersion forces in CH4.
  • (C) CH4 is a polar molecule while NH3 is nonpolar.
  • (D) NH3 has a more symmetrical molecular structure than CH4.
View Answer

Answer Explanation:

Ammonia (NH3) can form hydrogen bonds due to the presence of a lone pair on nitrogen and hydrogen atoms bonded to a highly electronegative atom. Methane (CH4) is nonpolar and only exhibits weak London dispersion forces, resulting in a lower boiling point.

Correct Answer: (B) NH3 has stronger hydrogen bonds compared to the London dispersion forces in CH4.


Question 63:

Which of the following types of bonding is primarily responsible for the high melting point and hardness of diamond?

Options:

  • (A) Metallic bonding
  • (B) Ionic bonding
  • (C) Covalent network bonding
  • (D) Van der Waals forces
View Answer

Answer Explanation:

Diamond is a network covalent solid where each carbon atom forms four strong covalent bonds in a 3D lattice, resulting in extremely high melting points and hardness.

Correct Answer: (C) Covalent network bonding


Question 64:

Which of the following best explains why hydrogen fluoride (HF) has a higher boiling point than hydrogen chloride (HCl)?

Options:

  • (A) HF has stronger hydrogen bonding due to the higher electronegativity of fluorine compared to chlorine.
  • (B) HCl has stronger dipole-dipole interactions than HF.
  • (C) HF has a larger molecular size than HCl.
  • (D) HCl forms a network covalent structure, unlike HF.
View Answer

Answer Explanation:

Fluorine is more electronegative than chlorine, allowing HF molecules to form stronger hydrogen bonds compared to the dipole-dipole interactions in HCl, resulting in a higher boiling point.

Correct Answer: (A) HF has stronger hydrogen bonding due to the higher electronegativity of fluorine compared to chlorine.


Question 65:

Which of the following molecules has a linear geometry due to sp hybridization?

Options:

  • (A) BeCl2
  • (B) SO2
  • (C) NH3
  • (D) H2O
View Answer

Answer Explanation:

Beryllium chloride (BeCl2) has a linear geometry with sp hybridization, as it has two bonding pairs and no lone pairs around the central atom.

Correct Answer: (A) BeCl2


Question 66:

Which of the following molecules exhibits hydrogen bonding in the liquid state?

Options:

  • (A) Hydrogen sulfide (H2S)
  • (B) Methane (CH4)
  • (C) Ethanol (C2H5OH)
  • (D) Carbon tetrachloride (CCl4)
View Answer
   

Answer Explanation:

Ethanol has an -OH group, allowing it to form hydrogen bonds in the liquid state.

Correct Answer: (C) Ethanol (C2H5OH)


Question 67:

Which of the following best explains why magnesium oxide (MgO) has a higher lattice energy than sodium chloride (NaCl)?

Options:

  • (A) MgO has larger ions than NaCl.
  • (B) MgO has ions with higher charges than NaCl.
  • (C) NaCl has a higher charge density than MgO.
  • (D) NaCl forms stronger metallic bonds than MgO.
View Answer

Answer Explanation:

Magnesium oxide (MgO) consists of Mg2+ and O2- ions, which have higher charges compared to the +1 and -1 charges in sodium chloride (NaCl). According to Coulomb’s Law, higher charges result in greater lattice energy.

Correct Answer: (B) MgO has ions with higher charges than NaCl.


Question 68:

Which of the following molecules has a see-saw molecular geometry due to the presence of one lone pair on the central atom?

Options:

  • (A) SF4
  • (B) PCl5
  • (C) ClF3
  • (D) XeF2
View Answer
   

Answer Explanation:

SF4 has a see-saw geometry with four bonding pairs and one lone pair on the central sulfur atom.

Correct Answer: (A) SF4


Question 69:

Which of the following statements correctly describes the relationship between molecular geometry and hybridization?

Options:

  • (A) All linear molecules have sp3 hybridization.
  • (B) Tetrahedral molecules have sp3 hybridization.
  • (C) Trigonal pyramidal molecules have sp2 hybridization.
  • (D) Bent molecules have sp hybridization.
View Answer

Answer Explanation:

Tetrahedral molecules, such as CH4, have sp3 hybridization.

Correct Answer: (B) Tetrahedral molecules have sp3 hybridization.


Question 70:

Which of the following best explains why silicon dioxide (SiO2) has a high melting point?

Options:

  • (A) It forms discrete molecules with strong hydrogen bonds.
  • (B) It has a network of strong covalent bonds throughout the structure.
  • (C) It consists of small ions held together by ionic bonds.
  • (D) It has delocalized electrons that contribute to metallic bonding.
View Answer

Answer Explanation:

Silicon dioxide (SiO2) is a network covalent solid with each silicon atom covalently bonded to four oxygen atoms in a continuous network, requiring a large amount of energy to break these bonds, resulting in a high melting point.

Correct Answer: (B) It has a network of strong covalent bonds throughout the structure.


Question 71:

Which of the following best explains why metals like copper can conduct electricity, while non-metals like sulfur cannot?

Options:

  • (A) Metals have free-moving electrons that can carry an electric charge, whereas non-metals do not have such free electrons.
  • (B) Non-metals have more protons that block electron movement, preventing electrical conductivity.
  • (C) Metals form ionic bonds that allow for the free flow of electrons, while non-metals form covalent bonds.
  • (D) Non-metals have delocalized electrons that prevent electrical conductivity, while metals do not.
View Answer

Answer Explanation:

Metals have free-moving electrons that can carry an electric charge, allowing them to conduct electricity. Non-metals, on the other hand, do not have such free electrons to support electrical conductivity.

Correct Answer: (A) Metals have free-moving electrons that can carry an electric charge, whereas non-metals do not have such free electrons.


Question 72:

Which of the following best explains why ionic bonds generally result in high melting and boiling points?

Options:

  • (A) Ionic bonds involve the sharing of electrons, creating strong covalent bonds.
  • (B) Ionic bonds involve the electrostatic attraction between ions, which requires significant energy to overcome.
  • (C) Ionic bonds allow for the delocalization of electrons, enhancing bond strength.
  • (D) Ionic bonds are weaker than metallic bonds, leading to higher melting points.
View Answer

Answer Explanation:

Ionic bonds are strong electrostatic attractions between oppositely charged ions in a lattice structure, requiring significant energy to break, which results in high melting and boiling points.

Correct Answer: (B) Ionic bonds involve the electrostatic attraction between ions, which requires significant energy to overcome.


Question 73:

Which of the following best describes the intermolecular forces present in silicon dioxide (SiO2)?

Options:

  • (A) Hydrogen bonds
  • (B) Dipole-dipole interactions
  • (C) London dispersion forces
  • (D) Network covalent bonds
View Answer

Answer Explanation:

Silicon dioxide (SiO2) is a network covalent solid where atoms are bonded through strong covalent bonds in an extensive 3D network, rather than being held together by intermolecular forces.

Correct Answer: (D) Network covalent bonds


Question 74:

Which of the following molecules exhibits a net dipole moment?

Options:

  • (A) CO2
  • (B) BF3
  • (C) NH3
  • (D) C2H6
View Answer

Answer Explanation:

Ammonia (NH3) has a trigonal pyramidal geometry with a lone pair on nitrogen, resulting in an asymmetrical distribution of charge and a net dipole moment.

Correct Answer: (C) NH3


Question 75:

Which of the following statements about the properties of ionic solids is correct?

Options:

  • (A) Ionic solids are good conductors of electricity in their solid state.
  • (B) Ionic solids have low melting points due to weak forces between ions.
  • (C) Ionic solids are brittle and shatter when force is applied.
  • (D) Ionic solids are malleable like metals.
View Answer

Answer Explanation:

Ionic solids consist of a lattice of positively and negatively charged ions held together by strong electrostatic forces. Their properties are distinct from those of metals and molecular solids:

  • Option A: Incorrect. Ionic solids are poor conductors of electricity in their solid state because ions are fixed in place. They conduct electricity when molten or dissolved in water, where the ions are free to move.
  • Option B: Incorrect. Ionic solids have high melting points due to the strong electrostatic forces between ions.
  • Option C: Correct. Ionic solids are brittle because when a force is applied, it causes a shift in the lattice, bringing like charges into alignment and resulting in repulsion that shatters the solid.
  • Option D: Incorrect. Ionic solids are not malleable; they are brittle and will break under stress.

Correct Answer: (C) Ionic solids are brittle and shatter when force is applied.


Question 76:

Which of the following molecules is nonpolar due to its symmetrical geometry despite having polar bonds?

Options:

  • (A) Water (H2O)
  • (B) Carbon tetrachloride (CCl4)
  • (C) Ammonia (NH3)
  • (D) Hydrogen fluoride (HF)
View Answer
   

Answer Explanation:

Carbon tetrachloride (CCl4) has polar C-Cl bonds, but the tetrahedral symmetry causes the dipole moments to cancel out, making it a nonpolar molecule.

Correct Answer: (B) Carbon tetrachloride (CCl4)


Question 77:

Which of the following best explains why hydrogen bonds are stronger than London dispersion forces?

Options:

  • (A) Hydrogen bonds involve the sharing of electrons between atoms.
  • (B) Hydrogen bonds occur between molecules with highly electronegative atoms bonded to hydrogen, creating strong dipoles.
  • (C) London dispersion forces are a type of hydrogen bonding.
  • (D) Hydrogen bonds are weaker than dipole-dipole interactions.
View Answer

Answer Explanation:

Hydrogen bonds are stronger than London dispersion forces because they involve highly electronegative atoms (like N, O, F) bonded to hydrogen, creating strong dipoles that attract each other more effectively than the temporary dipoles involved in London dispersion forces.

Correct Answer: (B) Hydrogen bonds occur between molecules with highly electronegative atoms bonded to hydrogen, creating strong dipoles.


Question 78:

Which of the following molecules exhibits sp3 hybridization at the central atom?

Options:

  • (A) CO2
  • (B) NH3
  • (C) BF3
  • (D) XeF4
View Answer

Answer Explanation:

Ammonia (NH3) has three bonding pairs and one lone pair, resulting in sp3 hybridization at the nitrogen atom.

Correct Answer: (B) NH3


Question 79:

Which of the following network covalent solids has a layered structure allowing it to be soft (애매함) and slippery?

Options:

  • (A) Diamond (C)
  • (B) Silicon (Si)
  • (C) Graphite (C)
  • (D) Silicon Dioxide (SiO2)
View Answer

Answer Explanation:

Graphite has a layered structure where each layer is held together by weak van der Waals forces, allowing layers to slide over each other, making graphite soft and slippery.

Correct Answer: (C) Graphite (C)


Question 80:

Which of the following best explains why network covalent solids like diamond and silicon dioxide do not conduct electricity?

Options:

  • (A) They lack delocalized electrons.
  • (B) They have high lattice energies.
  • (C) They have symmetrical molecular geometries.
  • (D) They possess lone pairs of electrons.
View Answer

Answer Explanation:

Network covalent solids like diamond and silicon dioxide have all their electrons involved in strong covalent bonds, leaving no delocalized electrons available to conduct electricity.

Correct Answer: (A) They lack delocalized electrons.


Question 81:

Which of the following best describes the process of bond formation in covalent bonds?

Options:

  • (A) Electrons are transferred from one atom to another.
  • (B) Electrons are shared between two atoms.
  • (C) Electrons become delocalized over a metal lattice.
  • (D) Electrons are removed entirely from a molecule.
View Answer

Answer Explanation:

Covalent bonds are formed by the sharing of electrons between two atoms, allowing each atom to achieve a stable electron configuration.

Correct Answer: (B) Electrons are shared between two atoms.


Question 82:

Which of the following statements correctly describes the relationship between bond energy and potential energy during bond formation?

Options:

  • (A) Bond energy decreases as potential energy decreases.
  • (B) Bond energy is inversely related to potential energy.
  • (C) Bond energy is directly proportional to the difference in potential energy before and after bond formation.
  • (D) Bond energy and potential energy are unrelated concepts.
View Answer

Answer Explanation:

Bond energy is the difference in potential energy between the bonded state and the separated atoms. It is directly proportional to the energy required to break the bond (bond dissociation energy).

Correct Answer: (C) Bond energy is directly proportional to the difference in potential energy before and after bond formation.


Question 83:

Which of the following best explains why methane (CH4) has a tetrahedral geometry?

Options:

  • (A) It has sp2 hybridization.
  • (B) It has sp3 hybridization with no lone pairs.
  • (C) It has sp hybridization with two lone pairs.
  • (D) It has dsp3 hybridization.
View Answer

Answer Explanation:

Methane (CH4) has sp3 hybridization, resulting in four equivalent bonding pairs arranged in a tetrahedral geometry with no lone pairs on the carbon atom.

Correct Answer: (B) It has sp3 hybridization with no lone pairs.


Question 84:

Which of the following best describes the trend in bond strength among the following hydrogen halides: HF, HCl, HBr, and HI?

Options:

  • (A) HF > HCl > HBr > HI
  • (B) HI > HBr > HCl > HF
  • (C) HCl > HF > HI > HBr
  • (D) HBr > HI > HF > HCl
View Answer

Answer Explanation:

Bond strength decreases as bond length increases. HF has the shortest and strongest bond, followed by HCl, HBr, and HI with the longest and weakest bonds.

Correct Answer: (A) HF > HCl > HBr > HI


Question 85:

Which of the following best explains why hydrogen sulfide (H2S>) has a lower boiling point than hydrogen peroxide (H2O2)?

Options:

  • (A) H2S has stronger hydrogen bonds than H2O2.
  • (B) H2O2 has stronger hydrogen bonds due to the presence of additional hydroxyl groups.
  • (C) H2S is a larger molecule, resulting in weaker intermolecular forces.
  • (D) H2O2 has a higher molecular weight, leading to lower boiling points.
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Answer Explanation:

Hydrogen peroxide (H2O2) can form more extensive hydrogen bonding due to the presence of two hydroxyl groups, resulting in stronger intermolecular forces and a higher boiling point compared to hydrogen sulfide (H2S), which primarily exhibits weaker dipole-dipole interactions and London dispersion forces.

Correct Answer: (B) H2O2 has stronger hydrogen bonds due to the presence of additional hydroxyl groups.


Question 86:

Which of the following best explains the difference in electrical conductivity between metallic solids and molecular solids?

Options:

  • (A) Metallic solids have delocalized electrons that can move freely, while molecular solids do not.
  • (B) Molecular solids have delocalized electrons, while metallic solids do not.
  • (C) Both metallic and molecular solids have delocalized electrons, but molecular solids have stronger bonds.
  • (D) Neither metallic nor molecular solids have delocalized electrons.
View Answer

Answer Explanation:

Metallic solids have delocalized electrons that can move freely throughout the lattice, allowing them to conduct electricity. Molecular solids lack such free electrons, making them poor conductors.

Correct Answer: (A) Metallic solids have delocalized electrons that can move freely, while molecular solids do not.


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